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# numpy.emath.arccos

emath.arccos(x)

  Compute the inverse cosine of x.

  Return the “principal value” (for a description of this, see `numpy.arccos`) of the inverse cosine of x. For real x such that abs(x) <= 1, this is a real number in the closed interval \([0, \pi]\). Otherwise, the complex principle value is returned.

  Parameters:
    x array_like or scalar

      The value(s) whose arccos is (are) required.

  Returns:
    out ndarray or scalar

      The inverse cosine(s) of the x value(s). If x was a scalar, so is out, otherwise an array object is returned.

  See also

  `numpy.arccos`

  Notes

  For an arccos() that returns `NAN` when real x is not in the interval `[-1,1]`, use `numpy.arccos`.

  Examples

      >>> import numpy as np
      >>> np.set_printoptions(precision=4)

      >>> np.emath.arccos(1) # a scalar is returned
      0.0

      >>> np.emath.arccos([1,2])
      array([0.-0.j   , 0.-1.317j])